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0.09-1.8x+8x^2=0
a = 8; b = -1.8; c = +0.09;
Δ = b2-4ac
Δ = -1.82-4·8·0.09
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.8)-\sqrt{0.36}}{2*8}=\frac{1.8-\sqrt{0.36}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.8)+\sqrt{0.36}}{2*8}=\frac{1.8+\sqrt{0.36}}{16} $
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